Apolynomial function, f(x), with rational coefficients has roots of –2 and square root of 3. the irrational conjugates theorem states that which of the following must also be a root of the function?

if 2 + √3 is an irrational root to a polynomial, then its irrational conjugate 2- √3 is also.

Step-by-step explanation:

Given : A polynomial function, f(x), with rational coefficients has roots of –2 and square root of 3.

To find :  which of the following must also be a root of the function?

Solution : We have root of  f(x)  = 2 +√3.

By the  irrational conjugates theorem : it state that  states that if   a + √b is an irrational root to a polynomial, then its irrational conjugate a - √b is also

root.

Therefore, if 2 + √3 is an irrational root to a polynomial, then its irrational conjugate 2- √3 is also.

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept