![A= \cfrac{3 \sqrt{3} }{2}*a^2 \ \ \ \ [a=sidelength] \\ \\ a=48/6=8 \ in \\ \\ \\ A= \cfrac{3 \sqrt{3} }{2}*(8)^2=A= \cfrac{3 \sqrt{3} }{2}*64=3 \sqrt{3}*32= 96 \sqrt{3} \ \ in^2](/tpl/images/0217/4492/6a00c.png)
Find the area of a regular hexagon with a 48-inch perimeter.
48β3 in2
96β3 in2
192...
Mathematics, 01.09.2019 10:00 marziel24
Find the area of a regular hexagon with a 48-inch perimeter.
48β3 in2
96β3 in2
192β3 in2
in2 means inches squared
Answers: 3
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