If z=2.5, x=102 and x=100, what is s?

I believe the problem ask for s which is the standard deviation. We must recall that the formula for z statistic is stated as:

z = (x – x over bar) / s

Where,

z = z statistic = 2.5

x = sample value or sample score = 102

x over bar = the sample mean or sample average  = 100

s = standard deviation = unknown

Rewriting the equation in terms of s:

s = (x – x over bar) / z

Substituting the given values into the equation:

s = (102 – 100) / 2.5

s = 0.8  

Therefore the standard deviation s is 0.8

65

step-by-step explanation:

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