Determine the discriminant for the quadracic equation 0=-2x^2+3. based on the discriminant value, how many real number solutions does the equation have?
discriminant = b^2-4ac
? real number solutions

We are gonna use the formula "Discriminant = b^2-4ac" here to determine the discriminant. We have the value of a=-2; b=0; and c=3. Substituting the values to the formula, we can get the discriminant which is 24. We will then use  the rule of discriminant in this problem: 
If b² - 4ac > 0, there are two real number solutions  
If b² - 4ac = 0, there is one real number solution  
If b² - 4ac < 0, there are two imaginary number solutions  
Therefore, we can conclude that there will be two real numbers solutions since the discriminant is greater than 0.

It’s 24.6 after you round to the nearest tenths the answer should be 25.0