The triangle jkl shown on the coordinate grid below is reflected once to map onto triangle j'k'l': triangle jkl is drawn on a 4 quadrant coordinate grid with vertices j is at 8, 1. k is at 5, 7. l is at 3, 4. if vertex l' is at (−3, 4), what are the coordinates of vertex j'?

The vertex J' is at (-8,1).

Step-by-step explanation:

If is given that the triangle JKL reflected once to map onto triangle J'K'L'.

The vertices of the triangle JKL are J(8,1), K(5,7) and L(3,4). The vertex L'(-3,4).

It is in the form of

Since the y-coordinate remains same and the sign of x coordinate is changed. It shows the reflection across the y axis.

The vertices of image are,

Therefore the vertex J' is at (-8,1).

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !