What is the velocity of an object that has fallen 76 feet

Ignoring air resistance...

vf^2-vi^2=2gs, where vf is final velocity, vi=initial velocity, g=acceleration due to gravity, and s is the displacement of the object...

For an object being dropped, vi=0, so we have only have final velocity.

v^2=2gs

v=-√(2gs), g≈-32ft/s^2, s=-76

v=-√(2(-32)(-76))

v=-√4864

v≈ -69.74 ft/s  (to nearest hundredth of a foot per second)

It's negative because the object is falling, or height is decreasing :P

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!