The height of 18-year-old men are approximately normally distributed, with mean of 68 inches and a standard deviation of 3 inches. what is the probability that an 18-year-old man selected at random is between 67 and 69 inches tall? round your answer to the nearest thousandths place (3 places).the height of 18-year-old men are approximately normally distributed, with mean of 68 inches and a standard deviation of 3 inches. what is the probability that an 18-year-old man selected at random is between 67 and 69 inches tall? round your answer to the nearest thousandths place (3 places).

The bell curve below shows the location of the mean and the two values of X; 67 and 69

The area under the curve equals to 1 (as probability equals to one)

We want the area between X=67 and X=69

We first need to find the z-score of X=67 and X=69

z-score of X=67 is given by 
z-score of X=69 is given by 

The area between z-score -0.33 and 0.33 is given by 
P(Z<0.33) - P(Z<-0.33)

We need to read off the z-table to find the value of P(Z<0.33) and P(Z<-0.33).
A screenshot of the z-table is shown below

P(Z<-0.33) = 0.3707
P(Z<0.33) = 0.6293

Hence, the probability that an 18-year old man  selected at random is between 67 and 69 inches tall is 0.6293-0.3707=0.2586 or 25.86%

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm