Determine the equation of the line with slope −2 that passes through the point m(−1, −3).
2x + y = −5
2x − y = −5
x − 2y = 5
x − 2y = −5

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )