When a crew rows with the current, it travels 18 miles in 3 hours. against the current, the crew rows 6 miles in 3 hours. let x=the crew's rowing rate in still water and let y = the rate of the current. find the rate of rowing in still water and the rate of the current.

The speed of the boat in still water is 4mph and the speed of the current is 2mph.

Using the distance formula expressed as:

Distance = speed * time

d = st

Let x be the crew's rowing rate in still water and;

let y be the rate of the current

If a crew rows with the current and it travels 18 miles in 3 hours, the

3(x+y)=18

If they row against the current, the crew rows 6 miles in 3 hours then;

3(x-y)=6  

The equations becomes

x + y = 6

x - y = 2

Add both equations

2x = 6 + 2

2x = 8

x = 4

Recall that x + y = 6

4 + y = 6

y = 2

Hence the speed of the boat in still water is 4mph and the speed of the current is 2mph.

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what do you need me to answer?

step-by-step explanation:

17   x 256=4352

sorry if this is wrong, i'm new.

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