Raj fully simplified the polynomial and then put it in standard form with the last term being 6y3. 2x2y + 8x3 – xy2 – 2x3 + 3xy2 + 6y3 what is the first term of the polynomial raj ended up with?
a 6x3
b 8x3
c 2xy2
d 3xy2

 The correct option is (a).

Step-by-step explanation:  Given that Raj fully simplifies the following polynomial and put it in standard form.

We are to find the first term of his polynomial Raj ended up with if the last term he wrote was

We know that

if all the terms of a POLYNOMIAL in two variables x and y has same degree, then in the standard form, it can be written in the descending power of x and ascending power of y,

or, ascending powers of x and descending powers of y.

Since all the terms in Raj's polynomial is of degree 3, and the last term is [/tex]6y^3,[/tex] which contains the highest power of y.

So, the polynomial has ascending powers of y, and consequently, it will have descending powers of x.

So, the polynomial in standard form will be

Therefore, the first term in Raj's polynomial is

Option (a) is correct.

answer: about 22.67

step-by-step explanation:

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.