Which of the following equations represents a quadratic function?

y(y + 4)(y - 6) = 0
z2 + 2 = 3z(z2 - 1)
(2x - 3)(4x + 5) = 10x
(3b)(5b – 7)(b + 8) = 0

A quadratic equation is one in which the highest exponent of a variable is 2. We can solve this problem by expanding each choices then find which has highest exponent equal to 2.

y(y + 4)(y - 6) = 0           ---> By expansion we get y^3, therefore highest exponent is 3.

z2 + 2 = 3z(z2 - 1)          ---> By expansion we get z^3, therefore highest exponent is 3.

(2x - 3)(4x + 5) = 10x     ---> By expansion we get x^2, therefore highest exponent is 2.

(3b)(5b – 7)(b + 8) = 0    ---> By expansion we get b^3, therefore highest exponent is 3.

The answer to this problem is therefore:

(2x - 3)(4x + 5) = 10x

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13