Aplane takes off at an angle of elevation of 15 degrees and travels in a straight line for 3000 meters what is the height of the plane above the ground at this instant

Sinα=height/hypotenuse

height=hypotenuse*sinα, 

We are given that hypotenuse is 3000m and α=15 so

h=3000sin15° m

h≈776.46 m  (to nearest hundredth of a meter or to the nearest centimeter)

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3