What is the equation of the line that is parallel to y=-2/3x+4 and that passes through (–2,–2)?

answers
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y=-2/3x-4/3
y=-2/3x-10/3
y=-2/3x-2/3
y=-2/3x-17/4

For lines to be parallel to one another they must have the same slope.  Our reference line has a slope of -2/3, so our parallel line is:

y=-2x/3+b, using the point (-2,-2) we can solve for "b", the y-intercept.

-2=-2(-2)/3+b

-2=4/3+b

-6/3-4/3=b

-10/3=b so our line is:

y=-2x/3-10/3  (or more neatly in my opinion :P)

y=(-2x-10)/3

It's the second one down from the top :)