What are the sine, cosine, and tangent of θ = 7 pi over 4 radians?

sin θ = negative square root 2 over 2; cos θ = negative square root 2 over 2; tan θ = 1

sin θ = negative square root 2 over 2; cos θ = square root 2 over 2; tan θ = 1

sin θ = square root 2 over 2; cos θ = negative square root 2 over 2 tan θ = −1

sin θ = negative square root 2 over 2; cos θ = square root 2 over 2; tan θ = −1

Option D

Step-by-step explanation:

We are given an angle as

This angle lies between 3pi/2 and 2pi

i.e. in IV quadrant

In Iv quadrant only cos and secant are positive

sine and tangent would be negative

The principal value is pi/4 and for this tan =1

Hence we have

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = −1

Option D is right

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.