Find the 12th partial sum of the summation of negative 2i minus 10, from i equals 1 to infinity.
25
40
−276
72

The given equation is:

x = - 2i – 10

Calculating for values of i = 1 to 12

x (1) = -2 – 10 = -12

x (2) = -4 – 10 = -14

x (3) = -6 – 10 = -16

x (4) = -8 – 10 = -18

x (5) = -10 – 10 = -20

x (6) = -12 – 10 = -22

x (7) = -14 – 10 = -24

x (8) = -16 – 10 = -26

x (9) = -18 – 10 = -28

x (10) = -20 – 10 = -30

x (11) = -22 – 10 = -32

x (12) = -24 - 10 = -34

Getting the sum of all:

12th partial sum = -276

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)