Me find solutions to this equation and write the answers in radians in terms of pi .

Okay so just use it as an equation. 
if 2sin0 + 3^(1/2) = 0
2 sin0 = - 3^(1/2)
then sin0 = (-3^ (1/2))/2 
do sin^-1(-) 
= -1/3pi 
we want it between 0 < x < 2pi
so add 2pi (equivalent to 360degrees) 
= 5/3pi 
and to find the second value, (2pi - 5/3pi) + pi = 4/3pi
answers are 5/3pi and 4/3pi

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