The proof that δacb ≅ δecd is shown. given: ae and db bisect each other at c. prove: δacb ≅ δecd what is the missing statement in the proof? ∠bac ≅ ∠dec ∠acd ≅ ∠ecb ∠acb ≅ ∠ecd ∠bca ≅ ∠dca

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE    (Given)

BC=CD   (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD

Answer with explanation:

Given: It is given that , in ΔACB and ΔE CD , A E and DB bisect each other at C.

To Prove:  ΔA CB ≅ ΔE CD

Proof: In  ΔA CB ,and ΔE CD

A E and DB bisect each other at C.

AC=CE -------[Given]

          BC=CD-----[Given]

       ∠A CB = ∠E CD →→[Vertically opposite angles]

→∠A CB ≅ ∠E CD ⇒⇒[S A S]

Option C: →→∠A CB ≅ ∠E CD -------[missing statement in the proof]

it would be 6xy and -16xy.

3 is greater then both of those numbers