Jason has two bags with 6 tiles each.

without looking, jason draws a tile from the first bag and then a tile from the second bag. what is the probability of jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag?

assuming the tiles are numbered 1, 2, 3, 4, 5, 6

there is one tile with the number 2 on it in the first bag

 and 1 tile with the number 3 on it in the second bag

so you have a 1/6 probability of picking the 2 and a 1/6 probability of picking the 3

so 1/6 * 1/6 = 1/36 probability of picking them both

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

a

step-by-step explanation:

the answer is a