Brenda throws a dart at this square-shaped target: part a: is the probability of hitting the black circle inside the target closer to 0 or 1? explain your answer. (5 points) part b: is the probability of hitting the white portion of the target closer to 0 or 1? explain your answer. (5 points)

Either way.  The probability of hitting the circle is:

P(C)=Area of circle divided by area of square

P(W)=(area of square minus area of circle divided by area of square

P(C)=(πr^2)/s^2

P(W)=(s^2-πr^2)/s^2

...

Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:

P(inside circle)=π/121  (≈0.0259  or 2.6%)

P(outside circel)=(121-π)/121  (≈0.9744 or 97.4%)

5\16 x 2\5 = 10/80simplify to 1/80