The range of all real numbers x such that 2x − 5 < 7 or 4x + 10 > 6
a. (-1,6)
b. (-infinity, infinity)
c. an empty set
d. (6,-1)

First, simplify the two inequalities.

2x - 5 < 7
2x < 12 <-- Add 5 to each side
x < 6 <-- Divide both sides by 2

4x + 10 > 6
4x > -4 <-- Subtract both sides by 10
x > -1 <-- Divide both sides 4

Now we have the compound inequality x < 6 OR x > -1

To fulfill the first inequality, x has to be less 6. For the second inequality, x has to bigger than -1.

So, the answer is B. (-infinity, infinity).

Hey dear, hoping i'll be