Question 2(multiple choice worth 10 points) (08.03)carlton is using the following data samples to make a claim about the house values in his neighborhood: house value a $100,000 b $600,000 c $650,000 d $700,000 e $900,000 based on the data, should carlton use the mean or the median to make an inference about the house values in his neighborhood? he should use the median because there is an outlier that affects the mean. he should use the mean because there are no outliers that affect the mean. he should use the mean because it is in the center of the data. he should use the median because it is in the center of the data.

This verified guy is wrong, and all I can say is I resubmitted twice and it's not "He should use the median because it's the center of data" or "He should use the mean because there are no outliers that affect the mean."

Step-by-step explanation:

Actually, it's MEDIAN because there ARE outliers that affect the MEAN. If you take the mean, average, then the $2.5 M house will raise the mean.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this