Given f(x)= 17-x^2 what is the average rate of change in f(x) over the interval [1,5]

f(x)=−2x

x=1 

f(1)=−2

x=5

f(5)=−10

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-6 is your answer

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°