The probability that a fair coin tossed 10 times will land heads up on all ten tosses is 1 out of 2 10 210

The probability is:

Step-by-step explanation:

It is given that a fair coin is tossed 10 times.

As we know that each toss is independent of the other tosses.

Also the probability of turning up head and tail are equal and is equal to 1/2.

Hence, the probability of obtaining a head in all the 10 toss is calculated as:

Hence, the probability that the coin will turn up head in all the 10 tosses is:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116