Which statement shows the transitive property of equality? a. if ab = cd and ab =ef, then cd is not equal to ef. b. if ab + bc = de + bc, then ab = de. c. if ab = cd, and cd = de, then ab = de d. if ab = cd, then cd = ab.

c. If AB=CD and CD= DE ,then AB=DE.

Step-by-step explanation:

Statement of Transitive property of equality : It states that If two numbers are equal to third number then they are also equal to each other.

In short

 If a=b  and b= c

then a= c

a. AB= CD and AB=EF

Then CD=EF

But we are given that CD is not equal to EF. Therefore, it is false.

b.If AB+BC=DE+BC

Then , AB=DE , It is not a statement of transitive property of equality . When both sides added equal part of segment then the segments are equal.Therefore, it is not a transitive property. Hence,it is false.

c.If AB=CD and CD= DE

Then AB=DE

It follows the statement of transitive property . Therefore, it is true.

d. If AB=CD then CD=AB

It is a commutative property of equality . Therefore, it is not a statement of transitive property of equality.Hence, it is false.

Answer : c. If AB=CD and CD= DE ,then AB=DE.

i do not know the answer i am sorry

1/800 is the right answer