What are the vertical asymptotes of the function f(x) = 4x+8/x^2+3x-4

vertical asymptote at x=-4, 1

Step-by-step explanation:

To find vertical asymptote we set the denominator =0 and solve for x

Product is -4 and sum is +3

WE find out two factors whose sum is +3 and product is -4

Set each factor =0 and solve for x

vertical asymptote at x=-4, 1

answer: haha (: i’ll go see what it is

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.