How many three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9, if the digits can be repeated?if anyone can : ) 12 points

options:
a.) 64
b.) 100
c.)
125

100

B is correct

Step-by-step explanation:

If three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9

Here we have total number of digits are 5

We need to make 3-digit number which is greater than 200

First digit must be 2 or greater than 2

From list of number 1,2,6,7,9

Four numbers are greater than equal to 2

For 1st place total number of possibility = 4

For 2nd place number of possibility = 5

For 3rd place number of possibility = 5

Total numbers of which are greater than 200 = 4 x 5 x 5

                                                                            = 100

Hence, 100 three-digit number greater than 200

you can not drow on this

step-by-step explanation:

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb