Three students divided 53 base ten blocks equally among them. how many base ten blocks does each student receive? how many were left over?

51 is the highest multiple you can take from 53

One way to find this out is take 53-30 and you get 23 from this you know 21 is the highest multiple you can get so 30+21 = 51

51/3 is 17 so each student gets 17 blocks and the thus remainder is 2

Another way is to divide 30 and 21 by 3 and add them both together and you will get the same answer

Do always make the numbers easier to solve and save time scrambling..

the answer would be c ≈ 18.852*3.14= 6.286.28*3=18.85