Simplify the radical expression. 2 sqrt6 + 3 sqrt 96
a)14 sqt 6
b)14 sqrt 96
c)5 sqrt 96
d)5 sqrt 6

First break down 96 into the smaller factors of 6 and 16


Now the square root of 16 comes out even as 4 so you can evaluate that part.


Multiply 3 and 4 to get 12


And now that the square roots on both parts of the eqations are the same you can add them to get: 

Therefore your answer is a