Solve for x

1. log(x+9)=log(2x-7)

2. log(x-1)^2=log(-5x-1)

Lets first solve the first one:

log(x+9)=log(2x−7)

Convert the logarithmic equation to an exponential equation.

10^log(x+9)=10^log(2x−7)

Remember that 10^logx=x, so

x+9=2x−7

Move values with 'x' to the right hand side.

7+9=2x-x

Combine like terms.

16=x so,

x=16

Check:

log(x+9)=log(2x−7)

If x=16

log(16+9)=log(2(16)−7)

log25=log(32−7)

log25=log25

x=16 is a solution.

Solve the second one like i solved this one, try it

5/20 so 25%

step-by-step explanation: