Four circles, each with a radius of 2 inches, are removed from a square. what is the remaining area of the square? (16 – 4π) in.2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2

Because each circle has radius = 2 in, each side of the square is 4*2 = 8 in.
The area of the square is 8^2 = 64 in^2

The area of one circle is π*2^2 = 4π in^2
The area of 4 circles is  4*(4π) = 16 in^2

The remaining area of the square is
(64 - 16π) in^2

50 % is the answer !