Y=-6x^2+100x-180 what are the zeroes of the function? round to the nearest hundredth.

Use the quadratic formula to solve it:
Y= -6x^2 +100x -180

a= -6
b= 100
c= -180

x = [-b +- sq root(b^2 - 4ac)] / 2a
x = [-100 +- sq root (10,000 -4*-6*-180)] / -12
x = [-100 +- sq root (10,000 -4,320)] / -12
x = [-100 +- sq root (5,680)] / -12
x1 = (-100 + 75.3658 ) / -12
x1 = 24.6342 / -12
x1 = -2.05285

x2 = (-100  - 75.3658 ) / -12
x2 = (- 175.3658 ) / -12
x 2 = 14.6138