The length of a rectangle is 6 inches more than 4times the width. the perimeter is
142inches. find the length and the width.

P = 2(L + W)
P = 142
L = 4W + 6

142 = 2(4W + 6 + W)
142 = 2(5W + 6)
142 = 10W + 12
142 - 12 = 10W
130 = 10W
130/10 = W
13 = W <=== width

L = 4W + 6
L = 4(13) + 6
L = 52 + 6
L = 58 <== length

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

What is the number for e if you don't knkw then there is no answer you need that number to plug in then multiply that number with 5.9 then add 10