The current size of an image on sandra's computer is shown below:

a rectangle is shown. the length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

what are the dimensions of the image at fraction 1 over 2 times its current size?

a. length = 4 inches, width = 6 inches
b. length = 3 inches, width = 4 inches
c. length = 8 inches, width = 10 inches
d. length = 12 inches, width = 16 inches

Option B is correct

Length = 3 inches, width = 4 inches

Step-by-step explanation:

As per the statement:

The current size of an image on Sandra's computer is shown below:

A rectangle is shown:

The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

⇒Length(l) = 6 inches and width(w) = 8 inches

We have to find the dimension of the image at fraction 1 over 2 times its current size.

Dimensions of the image at

then;

inches

and

inches

Therefore, the dimensions of the image at fraction 1 over 2 times its current size are:

Length = 3 inches, width = 4 inches

8y^50

step-by-step explanation: