The soccer team collected $800 at a car wash fundraiser. they charged $5.00 for small vehicles and $10.00 for larger vehicles. the amount collected can be modeled by the equation 5x + 10y = 800, where x represents the number of small vehicles and y represents the number of larger vehicles. if the number of larger vehicles washed was 50, how many small vehicles were washed in total?

Answer with Step-by-step explanation:

The soccer team collected $800 at a car wash fundraiser.

The amount charged for small vehicles=$5.00  

and amount charged for larger vehicles=$10.00

Let x represents the number of small vehicles and y represents the number of larger vehicles.

Then, 5x + 10y = 800

Now, when y=50

5x+10×50=800

i.e. 5x+500=800

i.e. 5x=800-500

i.e. 5x=300

Dividing both sides by 5, we get

x=60

Hence, number of  small vehicles washed in total is:

60

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

x/3-10=8

x/3=18

x=48