How many x intercepts appear on the graph of this polynomial function?
f(x) = x^4 - x^3 + x^2 - x
a) 1 x intercept
b) 2 x intercepts
c) 3 x intercepts
d) 4 x intercepts

The correct answer is B.

When you factor the polynomial you get the following:

f(x) = (x^2 + 1)(x)(x - 1)

The last two parenthesis give you the intercepts of 0 and 1. The first parenthesis will give you two non-real zeros, but these are not visible in a graph as the question asks.

14

step-by-step explanation:

14 x 3 = 42