There are ten pennies 14 nickels and 6 dimes in a bag and you remove 3 at a random without replacing any what is the probability you remove a penny and nickel and a dime in that order

There are 10+14+6=30 total coins in the bag including 10 pennies,14 buckles and 6 dimes
Then,
P(removing a penny after first pick):
10/30 or 1/3
Now, there are only 9 pennies, and total amount of coins decrease by one count which is 29
P(remove a nickel after second pick):
14/29
Now, there are only 28 coins in total left in the box, so
P(removing a dime):
6/28 or 3/14
Lastly, to find the probability or compound event, take:
1/3×14/29×3/14=42/1638
Simplify 42/1638
21/819. As a result, the probability you remove a penny and nickel and a dime in that order is 21/819. Hope it help!