What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)? y = –x + 33 y = –x + 36 y = 4x − 16 y = 4x + 16

Y=4x+16

If the line is parallel to y-1=4(x+3), the slope has to be the same, meaning that the slope has to be 4.
Putting this slope and the point into point slope form, we get the equation:

y-32=4(x-4)

Which can be simplified into slope intercept form:
y-32=4x-16
y=4x-16+32
y=4x+16