Aformula for a function y=f(x) is f(x)=x^2-10x, xless than or equal 5. find f^-1(x) and indentify the domain and range of f^-1(x). is f(f^-1(=f^-1(f(x))=x?

F(x) =x² - 10x,  f⁻¹(x) =?

1st find the missing square of x²-10x, ==> (x-5)² - 25

y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5

Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}

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