Giving medals find the area of the triangle with the given measurements. round the solution to the nearest hundredth if necessary. b = 104°, a = 11 cm, c = 18 cm 192.12 cm2 96.06 cm2 23.95 cm2 99 cm2

Option B is correct.

Step-by-step explanation:

Given: In a ΔABC, ∠B = 104° , a = 11 cm   and  c = 18 cm.

To find: area of the triangle.

We first find value of b using Law of cosines then using herons formula we find area of triangle.

Law of Cosines is a result used for calculating one side of a triangle when the angle opposite and the other two sides are known.

b² = a² + c² - 2ac × cos B

b² = 11² + 18² - 2 × 11 × 18 × cos 104°

b² = 445 - 396 × ( -0.24 )

b² = 540.04

b = 23.24 (nearest tenth)

Now, Herons Formula,

Semi perimeter,

Area of the triangle = 96.02 cm²

Therefore, Option B is correct.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2