Given: a rhombus is a quadrilateral with 4 congruent sides. prove: if quadrilateral abcd does not have 4 congruent sides, then it is not a rhombus. determine the first step to prove this statement using proof by contradiction.

A rhombus is by definition a quadrilateral all of whose sides are congruent (have the exact same length). To prove by contradiction, you have to assume that a quadrilateral ABCD does not have 4 congruent sides and is a rhombus, because that is against the definition.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

363 square inches

step-by-step explanation:

surface area of a pyramid is b + 1/2ph

b is the area of the base: 11 x 11 = 121

p is the perimeter of the base: 11 + 11 + 11 + 11 = 44

h is the height of the pyramid: 11

121 + 1/2(44)(11)

121 + 242

363