What must be given to prove that δbdf ~ δcae?

a.) ∠gbh ≅ ∠ich and ∠bfd ≅ ∠cea

b.) segment bh is congruent to segment ch & segment bg is congruent to segment ci

c.) ∠gbh ≅ ∠ich and ∠big ≅ ∠cgj

d.) segment bh is congruent to segment ch & segment hg is congruent to segment hi

The correct option is A.

Step-by-step explanation:

We have to prove ΔBDF and ΔCAE are similar.

Two triangles are called similar if  their corresponding interior angles are same or the corresponding sides are in a proportion.

According to the property of similarity, if two corresponding angles of triangles are same then the triangles are similar.

To prove,

The required conditions are

   .... (1)

  .... (2)

    .... (3)

If any two conditions from the above mentioned conditions are given then we can say that the ΔBDF and ΔCAE are similar.

Only option A satisfies the condition 1 and 3 because,

If these angles are congruent, then by AA rule of similarity ΔBDF and ΔCAE are similar.

Option A is correct.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

add the table and i will answer correctly

step-by-step explanation: