What is the value of x in the equation 1.8-3.7x=-4.2x+0.3

The value of x in the equation 1.8-3.7x=-4.2x+0.3 is - 3.

1.8 - 3.7x = -4.2x + 0.3

add 3.7x to both sides

1.8 - 3.7x + 3.7x = -4.2x + 3.7x + 0.3

1.8 = -0.5x + 0.3

subtract 0.3 from both sides

1.8 - 0.3 = -0.5x + 0.3 - 0.3

1.5  = - 0.5x

divide both sides by - 0.5x

1.5 / -0.5 = -0.5x / -0.5

x = - 3

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answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.