What is the equation of the line that passes through the point (3,0) and is perpendicular to the line 2x-y=5?

Passes through (3, 0) and is perpendicular to 2x - y = 5

Turn our given equation into y=mx+b form.

2x - y = 5

Subtract 2x from both sides.

-y = -2x + 5

Divide both sides by -1.

y = 2x - 5

So, our slope is 2.

However, because our equation is perpendicular, we must find the negative reciprocal of 2.

Slope₁ = 2

Slope₂ = -1/2

y - y₁ = m(x - x₁)   (3, 0)

Plug everything in.

y - 0 = -1/2(x - 3)

y = -1/2x + 3

~Hope I helped!~

It’s going to be d. 4x^2-4x-19’