In a hospital ward, there are 16 nurses and 5 doctors. 3 of the nurses and 3 of the doctors are male. if a person is randomly selected from this group, what is the probability that the person is male or a doctor?

Step-by-step explanation:

Given : In a hospital ward, there are 16 nurses and 5 doctors. 3 of the nurses and 3 of the doctors are male. If a person is randomly selected from this group.

To find : What is the probability that the person is male or a doctor?

Solution :

According to question,

The outcomes are not mutually exclusive, i.e, one does not exclude the others.

Total number of doctors = 16+5=21

Number of male = 3+3=6

Number of doctors = 5

Number of both male and doctor = 3

In probability - ("OR" → +)

If we do not subtract the people who are male and doctors, they will be counted twice.

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.