Which functions have real zeros at 1 and 4? check all that apply. a. f(x) = x2 + x + 4 b. f(x) = x2 – 5x + 4 c. f(x) = x2 + 3x – 4 d. f(x) = –2x2 + 10x – 8 e. f(x) = –4x2 – 16x – 1

Option B, D )the function has real zeros at x = 1 and x =4.

Step-by-step explanation:

Given : Real zero x = 1, x = 4.

To find : Which functions have real zeros at 1 and 4.

Solution : We have real zeros x =1 , x=4.

Factor theorem states that (x-r) is a factor of the polynomial function f(x) if and only if r is a root of the function f(x).

Since, we know that the root of the function i.e f(x) are -8 and 5 then the function has the following factor:

(x-1) = 0 and (x-4) =0

Zero product property states that if ab = 0 if and only if a =0 and b =0.

By zero product property,

(x-1)(x-4) = 0

Now, distribute each terms of the first polynomial to every term of the second polynomial we get;

Now, when you multiply two terms together you must multiply the coefficient (numbers) and add the exponent.

x(x-4) -1(x-4) = 0

= 0

Combine like terms;

= 0

Since B and we can see D

= 0

Taking common -2

-2() = 0

On dividing by -2 both side

Therefore,  Option B, D )the function has real zeros at x = 1 and x =4.

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

1/4 is the asnwer cuz 5/20 is the faction