The length of a rectangle picture frame is 3 inches greater than its width. the area if the picture frame is 40 square inches. find the dimensions of the picture frame

Let x be the width of the frame.

Then, x + 3 is the length of the frame.

The area of a rectangle is the product of its length and its width.

So, x(x+3) = 40

x^2 + 3x = 40

x^2 + 3x - 40 = 0

(x-5)*(x+8)=0

x-5 = 0 or x+8 = 0

x = 5 or x = -8

x = 5

The width is 5 and the length is 5 + 3 = 8

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group