Solve the following system of equations:

x − 2y = 6
2x − 4y = 10

infinitely many solutions

no solutions

(0, 0)

(6, 10)

Option B is the correct answer to this question. The following system of equations has No Solutions.

Step-by-step explanation:

Let's solve your system of equations

x − 2y = 6; 2x − 4y = 10

Step: Solve x − 2y = 6 for x:

x − 2y = 6

x − 2y + 2y = 6 + 2y (Add 2y to both sides)

x = 2y + 6

Step: Substitute 2y + 6 for (x) in 2x − 4y = 10:

2x − 4y = 10

2(2y + 6) −4y = 10

12 = 10 (Simplify both sides of the equation)

12 + −12 = 10 + −12 (Add -12 to both sides)

0 = −2

No Solutions

Source: https://www.mathpapa.com/calc/tutorial/solving-systems-of-equations/

,  Hope this helps :)

Have a great day!!

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts