What is the perimeter of the trapezoid with vertices q(8, 8), r(14, 16), s(20, 16), and t(22, 8)? round to the nearest hundredth, if necessary.\

The
according to the figure, the perimeter is 
QR + RS + ST+TQ = P
the distance QR = sqrt (6² + 8²) = 10
the distance RS = sqrt (6² + 0² = 6
the distance ST= sqrt (2² + 8²) = 8.24
the distance TQ = sqrt (14² + 0²) = 14
so finally the perimeter is P= QR + RS + ST+TQ = 10+6+8.24+14=38.24