In a city, 49% of the adults are male. of the adults, 24% are male and rent action-movie dvds and 10% are female and rent action-movie dvds. if an adult is randomly picked, the probability that the person rents action-movie dvds, given that the person is female, is .

The probability that the person rents action-movie DVDs, given that the person is female, is 0.1960 ≈ 19%

Step-by-step explanation:

Given :

Adults that are male = 49%.

Of the adults, 24% are male and rent action-movie DVDs

10% are female and rent action-movie DVDs.

Solution :

Since this is conditional probability, we only have to consider the given scenario where the person surveyed is female.

Now, 49% of the adult are males  .

So, adult females will be 100%-49% = 51%

Now, we need to calculate the probability that the person rents action-movie DVDs, given that the person is female:

since 10% females are those who rents action DVDs and total female adults are 51%

P(females are those who rents action DVDs ) = 0.1

P(total female adults ) = 0.51

P( females are those who rents action DVDs  | the person is female) = 0.1/0.51 =0.1960

Thus, the probability that the person rents action-movie DVDs, given that the person is female, is 0.1960 ≈ 19%

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!