An implicit equation for the plane passing through the points (1,3,−4), (−3,2,−7), and (1,0,−3) is

Given the points .

Need to find a plane equation that passes through the given points.

For this, find the cross product of .

×=

×=

×=

So, the normal to the plane is .

Definition: The plane equation that passes through the point  with normal is .

Here, and .

So,

Hence, the required plane equation in implicity form is .

For more information:

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .